1. An argon gas occupies 56.2 L at 760 torr. If the volume of gas is decreased to ¼ of the original volume, calculate it’s final pressure.
Answer :
Boyle’s law
There are several gas equations used, with various conditions. Boyle’s law studies the relationship between the pressure and volume of a gas. If the volume of gas is decreased to ¼ of the original volume, then the final pressure = 3040 torr = 4 atm
Further explanation
Some of the laws regarding gas, can apply to ideal gas :
- Boyle’s law at constant T, P = 1 / V
- Charles’s law, at constant P, V = T
- Avogadro’s law, at constant P and T, V = n
So that the three laws can be combined into a single gas equation, the ideal gas equation
PV = nRT
In Boyle’s law, it is stated that
In a closed system, the absolute pressure by an ideal gas is inversely proportional to the volume it occupies if the temperature is constant
PV = k
So it can be stated
Given
Volume of Argon gas : V₁=56.2 L
Pressure = P₁=760 torr
V₂ = ¼ of the original volume
Required
The final pressure, P₂
Solution
V₂ = ¼ of the original volume
V₂ = ¼ x 56.2 L
V₂ = 14.05 L
Input the value in formula :
Our team advises readers to look into the following questions :Culinary Arts: Then and Now
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